HAL_FORCE_MODIFY_U32_REG_FIELD macro
@cond Macro to force a 32-bit read, modify, then write on a peripheral register Due to a GCC bug, the compiler may still try to optimize read/writes to peripheral register fields by using 8/16 bit access, even if they are marked volatile (i.e., -fstrict-volatile-bitfields has no effect). For ESP chips, the peripheral bus only allows 32-bit read/writes. The following macro works around the compiler issue by forcing a 32-bit read/modify/write.
Syntax
#define HAL_FORCE_MODIFY_U32_REG_FIELD(base_reg, reg_field, field_val) \
{ \
uint32_t temp_val = base_reg.val; \
typeof(base_reg) temp_reg; \
temp_reg.val = temp_val; \
temp_reg.reg_field = (field_val); \
(base_reg).val = temp_reg.val; \
}
Notes
This macro should only be called on register fields of xxx_struct.h type headers, as it depends on the presence of a 'val' field of the register union. Current implementation reads into a uint32_t instead of copy base_reg direclty to temp_reg. The reason being that C++ does not create a copy constructor for volatile structs.