ot::Unequatable::operator!=() const method
Overloads operator `!=` to evaluate whether or not two instances of `Type` are equal. This is implemented in terms of an existing `==` overload provided by `Type` class itself.
Syntax
bool operator!=(const Type &aOther) const; Arguments
aOther
The other `Type` instance to compare with.
Return value
TRUE If the two `Type` instances are not equal. FALSE If the two `Type` instances are equal.
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bool operator!=(const Type &aOther) const { return !(*static_cast<const Type *>(this) == aOther); }
ot::Unequatable::operator!=() const is called by 1 function:
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ot::Unequatable::operator!=() const
ot::Unequatable::operator!=() const:
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ot::Unequatable::operator!=() const